Sideway
output.to from Sideway
Draft for Information Only

Content

Theory of Equation
 Biquadratic Equations
 Sources and References

Theory of Equation

Biquadratic Equations

492 Descurles' Solution: To solve the equation π‘₯4+π‘žπ‘₯2+π‘Ÿπ‘₯+𝑠=0i. the term in π‘₯3 having been removed by the method of (429). Assume (π‘₯2+𝑐π‘₯+𝑓)(π‘₯2βˆ’π‘π‘₯+𝑔)=0ii. Multiply out, and equate coefficients with [i.]; and the following equations for determining 𝑓, 𝑔, and 𝑐 are obtained 𝑔+𝑓=π‘ž+𝑐2, π‘”βˆ’π‘“=π‘Ÿπ‘, 𝑔𝑓=𝑠iii. 493 𝑐6+2π‘žπ‘4+(π‘ž2βˆ’4𝑠)𝑐2βˆ’π‘Ÿ2=0iv. 494 The cubic in 𝑐2 is reducible by Cardan's method, when the biquadratic has two real and two imaginary roots. For proof , take 𝛼±𝑖𝛽, and βˆ’π›ΌΒ±π›Ύ as the roots of [i.], since their sum must be zero. Form the sum of each pair for the values of 𝑐 [see [ii.]], and apply the rules in (488) to the cubic in 𝑐2.
If the biquadratic has all its roots real, or all imaginary roots of [i.], and form the values of 𝑐 as before. 495 If 𝛼2, 𝛽2, 𝛾2 be the roots of the cubic in 𝑒2, the roots of the biquadratic will be βˆ’12(𝛼+𝛽+𝛾), 12(𝛼+π›½βˆ’π›Ύ), 12(𝛽+π›Ύβˆ’π›Ό), 12(𝛾+π›Όβˆ’π›½) For proof, take 𝑀, π‘₯, 𝑦, 𝑧 for the roots of the biquadratic; then, by [ii.], the sum of each pair must give a value of 𝑒. Hence, we have only to solve the symmetrical equations. 𝑦+𝑧=𝛼, 𝑀+π‘₯=βˆ’π›Ό, 𝑧+π‘₯=𝛽, 𝑀+𝑦=βˆ’π›½, π‘₯+𝑦=𝛾, 𝑀+𝑧=βˆ’π›Ύ. 496 Ferrari's solution: To the left member of the equation π‘₯4+𝑝π‘₯3+π‘žπ‘₯2+π‘Ÿπ‘₯+𝑠=0 add the quantity π‘Žπ‘₯2+𝑏π‘₯+𝑏24π‘Ž, and assume the result =π‘₯2+𝑝2π‘₯+π‘š2 497 Expanding and equating coefficients, the following cubic equation for determining π‘š is obtained 8π‘š3βˆ’4π‘žπ‘š2+(2π‘π‘Ÿβˆ’8𝑠)π‘š+4π‘žπ‘ βˆ’π‘2π‘ βˆ’π‘Ÿ=0 then π‘₯ is given by the two quadratics π‘₯2+𝑝2π‘₯+π‘š=Β±2π‘Žπ‘₯+𝑏2π‘Ž 498 The cubic in π‘š is reducible by Cardan's method when the biquadratic has two real and two imaginary roots. Assume 𝛼, 𝛽, 𝛾, 𝛿 for the roots of the biquadratic; then 𝛼𝛽 and 𝛾𝛿 are the respective products of roots of the two quadratics above. From this find π‘š in terms of 𝛼𝛽𝛾𝛿. 499 Euler's solution: Remove the term in π‘₯3; then we have π‘₯4+π‘žπ‘₯2+π‘Ÿπ‘₯+𝑠=0 500 Assume π‘₯=𝑦+𝑧+𝑒, and it may be shewn that 𝑦2, 𝑧2, and 𝑒2 are the roots of the equation 𝑑3+π‘ž2𝑑2+π‘ž2βˆ’4𝑠16π‘‘βˆ’π‘Ÿ264=0 501 The six values of 𝑦, 𝑧, 𝑒, thence obtained, are restricted by the relation 𝑦𝑧𝑒=βˆ’π‘Ÿ8.
Thus π‘₯=𝑦+𝑧+𝑒 will take four different values.

Sources and References

https://archive.org/details/synopsis-of-elementary-results-in-pure-and-applied-mathematics-pdfdrive

Β©sideway

ID: 210800013 Last Updated: 8/13/2021 Revision: 0 Ref:

close

References

  1. B. Joseph, 1978, University Mathematics: A Textbook for Students of Science & Engineering
  2. Wheatstone, C., 1854, On the Formation of Powers from Arithmetical Progressions
  3. Stroud, K.A., 2001, Engineering Mathematics
  4. Coolidge, J.L., 1949, The Story of The Binomial Theorem
close

Latest Updated LinksValid XHTML 1.0 Transitional Valid CSS!Nu Html Checker Firefox53 Chromena IExplorerna
IMAGE

Home 5

Business

Management

HBR 3

Information

Recreation

Hobbies 8

Culture

Chinese 1097

English 339

Reference 79

Computer

Hardware 249

Software

Application 213

Digitization 32

Latex 52

Manim 205

KB 1

Numeric 19

Programming

Web 289

Unicode 504

HTML 66

CSS 65

SVG 46

ASP.NET 270

OS 429

DeskTop 7

Python 72

Knowledge

Mathematics

Formulas 8

Algebra 84

Number Theory 206

Trigonometry 31

Geometry 34

Coordinate Geometry 2

Calculus 67

Complex Analysis 21

Engineering

Tables 8

Mechanical

Mechanics 1

Rigid Bodies

Statics 92

Dynamics 37

Fluid 5

Fluid Kinematics 5

Control

Process Control 1

Acoustics 19

FiniteElement 2

Natural Sciences

Matter 1

Electric 27

Biology 1

Geography 1


Copyright © 2000-2024 Sideway . All rights reserved Disclaimers last modified on 06 September 2019