TOCForceMomentCoupleSystem of Forces Draft for Information Only
ContentEquilibrium of Rigid Body
Equilibrium of Rigid BodyA rigid body is in static equilibrium state when the rigid body remains stationary and is not accelerating in any way. In other words, a rigid body is in equilibrium when both the resultant force and the resultant moment are zero for all the forces and couples acting on it. Through system of forces transformation, an equivalent system of forces can be reduced to a force vector and a couple vector. Therefore the resultant force and the resultant couple vectors acting on the rigid body are equal to zero. That is: and Or in terms of rectangular components: and In other words, there is no translational and rotational motion when an object is in static equilibrium state. Free-BodyIn engineering static application, a rigid body is in equilibrium when the systems of external forces cause no translational and rotational motion to the rigid body since the resultant force and resultant memont on the rigid body are zero. For example, a hanging mass from the ceiling When solving the equilibrium problem of the considered body, in order to focus only on the interested body instead of the whole system, the interested body should be isolated from other bodies as a free body. According to Newton's third law, each applied force will have a reaction force of equal in magnitude and opposite in direction acting on the interacting bodies. Therefore, all the surrounding uninterested objects can be stripped away by replacing with the corresponding reaction force acting on the interesed body. For example, the interested objects are the mass and string. Therefore, a free body diagram can be drawn by adding a reaction force to replace the force due to the ceiling, while the body force due to the body mass remains unchange. Since the hanging string is also not an interested body, Imply the free body diagram of the body mass is : Free-Body DiagramImportant steps of constructing the free-body diagram are:
©sideway ID: 120200059 Last Updated: 2/15/2012 Revision: 0 Ref: References
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